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3-2.Motion in Plane
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Two projectiles are projected at $30^{\circ}$ and $60^{\circ}$ with the horizontal with the same speed. The ratio of the maximum height attained by the two projectiles respectively is:
A$2: \sqrt{3}$
B$\sqrt{3}: 1$
C$1: 3$
D$1: \sqrt{3}$
(JEE MAIN-2023) (AIIMS-2001)
Solution
$H _{\max }=\frac{ u ^2 \sin ^2 \theta}{2 g }$
$\frac{ H _1}{ H _2}=\frac{\sin ^2 \theta_1}{\sin ^2 \theta_2}=\frac{1}{3}$
$\frac{ H _1}{ H _2}=\frac{\sin ^2 \theta_1}{\sin ^2 \theta_2}=\frac{1}{3}$
Standard 11
Physics
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