For a satellite if time of revolution is T , then its K.E. is proportional to

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7.Gravitation

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For a satellite if the time of revolution is $T$, then its $K.E.$ is proportional to

A

$\frac{1}{T}$

B

$\frac{1}{T^2}$

C

$\frac{1}{T^3}$

D

$T^{-2/3}$

Solution

$\mathrm{kE}=\frac{\mathrm{GMm}}{2 \mathrm{r}}$

$\mathrm{kE} \propto \frac{1}{\mathrm{r}} \alpha \mathrm{T}^{\frac{-2}{3}}$

$\because\left(\mathrm{T}^{2} \alpha \mathrm{r}^{3}\right)$

Standard 11

Physics

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