For any reaction, if we plot a graph between time '$t$' and $\log (a - x)$, a simple line is obtained. The order of reaction is
$0$
$1$
$2$
$3$
During the kinetic study of the reaction, $2A + B \rightarrow C + D,$ following results were obtained
Run | $[A]/mol\,L^{-1}$ | $[B]/mol\,L^{-1}$ | Initial rate of formation of $D/mol\,L^{-1}\,min^{-1}$ |
$I.$ | $0.1$ | $0.1$ | $6.0 \times 10^{-3}$ |
$II.$ | $0.3$ | $0.2$ | $7.2 \times 10^{-2}$ |
$III.$ | $0.3$ | $0.4$ | $2.88 \times 10^{-1}$ |
$IV.$ | $0.4$ | $0.1$ | $2.40 \times 10^{-2}$ |
Based on the above data which one of the following is correct?
If the rate of the reaction is equal to the rate constant, the order of the reaction is
In the following reaction $A \to B + C$, rate constant is $0.001\, M/sec$. If we start with $1M$ of $A$, the conc. of $A$ & $B$ after $10$ min are respectively
Write unit of rate constant of following reaction :
$1.$ $\frac {1}{2}$ order
$2.$ $\frac {3}{2}$ order
$A + 2B \to C$, the rate equation for this reaction is given as Rate $= K[A][B]$ . If the concentration of $A$ is kept the same but that of $B$ is doubled what will happen to the rate it self ?