For acceleration-time (a-t) graph shown in figure, change in velocity of particle from t=0 to t=6 ,s

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2.Motion in Straight Line

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For the acceleration-time $(a-t)$ graph shown in figure, the change in velocity of particle from $t=0$ to $t=6 \,s$ is ........ $m / s$

A

$10$

B

$4$

C

$12$

D

$8$

Solution

(b)

Area under a-t graph gives change in velocity.

So, $\Delta v=\frac{1}{2} \times 4 \times 4-\frac{1}{2} \times 2 \times 4=8-4$

$\Delta v=4 ms ^{-1}$

Standard 11

Physics

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