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2.Motion in Straight Line
hard
The diagram shows the variation of $1 / v$ (where, $v$ is velocity of the particle) with respect to time. At time $t=3\,s$ using the details given in the graph, the instantaneous acceleration will be equal to $...........m/s^{2}$
A
$-2$
B
$+3$
C
$+5$
D
$-6$
Solution
(b)
$\frac{1}{v}$ versus $t$ equation from the given graph would be,
$\frac{1}{v}=\left(3+\frac{1}{\sqrt{3}}\right)-t$
$v=\frac{1}{\left(3+\frac{1}{\sqrt{3}}\right)-t}$
$a=\frac{d v}{d t}=\frac{1}{\left[\left(3+\frac{1}{\sqrt{3}}\right)-t\right]^2}$
Putting $t=3\,s$ we get, $a=3\,m / s ^2$.
Standard 11
Physics
