For circuit shown below, current through Zener diode is...... mA

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14.Semiconductor Electronics

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For the circuit shown below, the current through the Zener diode is......$mA$

A

$9$

B

$5$

C

$0$

D

$14$

(JEE MAIN-2019)

Solution

$\mathrm{I}_{10 \mathrm{k}}=\frac{50}{10 \mathrm{k}}=5\, \mathrm{mA}$

$\mathrm{i}_{5 \mathrm{k}}=\frac{120-50}{5 \mathrm{k}}=14\, \mathrm{mA}$

$\mathrm{i}_{2}=(14-5) \mathrm{mA}=9\, \mathrm{mA}$

Standard 12

Physics

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