14.Semiconductor Electronics
hard

For the given circuit, the power across zener diode is ..... ${mW}.$

A

$140$

B

$120$

C

$260$

D

$160$

(JEE MAIN-2021)

Solution

${i}=\frac{10 {V}}{5 {k} \Omega}=2 \,{mA}$

${I}=\frac{14 {V}}{1 {k} \Omega}=14 \,{mA}$

$\therefore {I}_{z}=12\, {mA}$

$\therefore {P}={I}_{z} {V}_{z}=120\, {mW}$

Standard 12
Physics

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