For the reaction $A \to B$, the rate increases by a factor of $2.25 $ when the concentration of $A$ is increased by $ 1.5$. What is the order of the reaction

  • A

    $3$

  • B

    $0$

  • C

    $2$

  • D

    $1$

Similar Questions

$A_2 + 2\,B \to 2\,AB$

$[A_2]$ $[B]$ ${-d\,[A_2]/dt}$
$0.1$ $0.2$ $1 \times {10^{ - 2}}\,M{s^{ - 1}}$
$0.2$ $0.2$ $2 \times {10^{ - 2}}\,M{s^{ - 1}}$
$0.2$ $0.4$ $8 \times {10^{ - 2}}\,M{s^{ - 1}}$

Order of reaction w.r.t. $A_2$ and $B$ are respectively

The mechanism of the reaction $A + 2B \to D$ is

$2B\xrightarrow{k}{B_2}$        [Slow]

${B_2} + A \to D$          [Fast]

The rate law expression, order with respect to $A$, order with respect to $'B'$ and overall order are respectively

Order of a reaction is decided by

If $‘a’ $ is the initial concentration and $ ‘n’ $ is the order of the reaction and the half life period is $ ‘T’,$  then

The results given in the below table were obtained during kinetic studies of the following reaction:

$2 A + B \longrightarrow C + D$

Experiment $[ A ] / molL ^{-1}$ $[ B ] / molL ^{-1}$ Initial $rate/molL$ $^{-1}$ $\min ^{-1}$
$I$ $0.1$ $0.1$ $6.00 \times 10^{-3}$
$II$ $0.1$ $0.2$ $2.40 \times 10^{-2}$
$III$ $0.2$ $0.1$ $1.20 \times 10^{-2}$
$IV$ $X$ $0.2$ $7.20 \times 10^{-2}$
$V$ $0.3$ $Y$ $2.88 \times 10^{-1}$

$X$ and $Y$ in the given table are respectively :

 

  • [JEE MAIN 2020]