Order of a reaction is decided by
Pressure
Temperature
Molecularity
Relative concentration of reactants
Consider the data given below for hypothetical reaction $A \to X$
$Time (sec)$ Rate $(mol\, L^{-1} sec.^{-1})$
$0$ $1.60 \times 10^{-2}$
$10$ $1.60 \times 10^{-2}$
$20$ $1.60 \times 10^{-2}$
$30$ $1.60 \times 10^{-2}$
From the above data, the order of reaction is
The rate law expression for the reaction $aA + bB \to P$ is rate $= K [A]^p [B]^q$ The order of the reaction is
The reaction ${N_2}{O_5}$ (in $CCl_4$ solution) $ \to 2N{O_2}$ (solution) $ + \frac{1}{2}{O_2}(g)$ is of first order in ${N_2}{O_5}$ with rate constant $6.2 \times {10^{ - 1}}{s^{ - 1}}.$ What is the value of rate of reaction when $[{N_2}{O_5}] = 1.25\,mole\,{l^{ - 1}}$
In a reaction involving hydrolysis of an organic chloride in presence of large excess of water$RCl + {H_2}O \to ROH + HCl$
The rate law for the reaction Sucrose + Water $\xrightarrow{{[{H^ + }]}}$ Glucose + Fructose is given by