Gujarati
Hindi
8.Mechanical Properties of Solids
hard

Force constant of a spring $(K)$ is synonymous to

A

$\frac{YA}{L}$

B

$\frac{YL}{A}$

C

$\frac{AL}{Y}$

D

$ALY$

Solution

$\mathrm{Y}=\frac{\mathrm{FL}}{\mathrm{A} \Delta \mathrm{L}}$

Or       $\mathrm{F}=\left(\frac{\mathrm{YA}}{\mathrm{L}}\right) \Delta \mathrm{L}$

Comparing this with $\mathrm{F}=\mathrm{K} \Delta \mathrm{L}$

$\mathrm{K}=\frac{\mathrm{YA}}{\mathrm{L}}$

Standard 11
Physics

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