ForceA particle moves with constant speed v along a circular path of radius r and completes circle i

English

Gujarati

Hindi

3-2.Motion in Plane

easy

forceA particle moves with constant speed $v$ along a circular path of radius $r$ and completes the circle in time $T$. The acceleration of the particle is

A$2\,\pi \,v/T$

B$2\,\pi \,r/T$

C$2\,\pi \,{r^2}/T$

D$2\,\pi \,{v^2}/T$

Solution

(a)Acceleration$ = {\omega ^2}r = \frac{{{v^2}}}{r} = \omega v = \frac{{2\pi }}{T}v$

Standard 11

Physics

Share

Similar Questions

A particle moving in a circle of radius $R$ with uniform speed takes time $\mathrm{T}$ to complete one revolution. If this particle is projected with the same speed at an angle $\theta$ to the horizontal, the maximum height attained by it is equal to $4 R$. The angle of projection $\theta$ is then given by :

hard

(JEE MAIN-2024)

If the equation for the displacement of a particle moving on a circular path is given by $(\theta ) = 2{t^3} + 0.5$, where $\theta $ is in radians and $t$ in seconds, then the angular velocity of the particle after $2 \,sec$ from its start is ……… $rad/sec$

easy

(AIIMS-1998)

Check up the only correct statement in the following :-

easy

The hour hand of a clock is $6\,cm$ long. The magnitude of the displacement of the tip of hour between $1:00\,PM$ to $5:00\,PM$ is

medium

The angular acceleration of a body, moving along the circumference of a circle, is :

easy

(NEET-2023)