Four tuning forks of frequencies 200,201, 204 | vedclass

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Question

$\left( {\frac{1}{1}} \right)$

$\left( {\left( {\frac{1}{2}} \right)} \right)\left( {\frac{2}{2}} \right)$

Vedclass · Accepted Answer

$12$

Vedclass · Answer

$\left( {\frac{1}{1}} \right)$

$\left( {\left( {\frac{1}{2}} \right)} \right)\left( {\frac{2}{2}} \right)$                      $\frac{1}{3}\left[ {\frac{2}{3}} \right]\left( {\frac{3}{3}} \right)$

$\frac{1}{4}\left( {\left( {\frac{2}{4}} \right)} \right)\frac{3}{4}\left( {\frac{4}{4}} \right)$                $\frac{1}{5}\frac{2}{5}\frac{3}{5}\frac{4}{5}\left( {\frac{5}{5}} \right)$

$\frac{1}{6}\frac{2}{6}\left( {\left( {\frac{3}{6}} \right)} \right)\left[ {\frac{4}{6}} \right]\frac{5}{6}\left( {\frac{6}{6}} \right)$

$Total =12$

Four tuning forks of frequencies $200,201, 204$ and $206\, Hz$ are sounded together. The beat frequency will be

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