Gujarati
Hindi
14.Waves and Sound
normal

The displacement of an elastic wave is given by the function : $y = 3\, sin\,\omega t + 4\, cos\,\omega t$ where $y$ is in $cm$ and $t$ is in $s$. The resultant amplitude is ...... $cm$

A

$3$

B

$4$

C

$5$

D

$7$

Solution

Resultant amplitude $ = \sqrt {{3^2} + {4^2}}  = \sqrt {9 + 16}  = 5\,cm$

Standard 11
Physics

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