Gujarati
14.Probability
easy

From a pack of $52$ cards two cards are drawn in succession one by one without replacement. The probability that both are aces is

A

$\frac{2}{{13}}$

B

$\frac{1}{{51}}$

C

$\frac{1}{{221}}$

D

$\frac{2}{{21}}$

Solution

(c) Required probability $ = \frac{4}{{52}}\,.\,\frac{3}{{51}} = \frac{1}{{221}}$.

Standard 11
Mathematics

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