From the $v-t$ graph, the
speed at $t = 1\,s$ is $1.2\, m/s$
acceleration is $2\, m/s^2$
average speed during $1^{st}\, second$ is $1.5\, m/s$
speed of the particle can be zero
What would be the stopping distance if the velocity of vehicle becomes three times ?
Mark the correct statements for a particle going on a straight line
A particle starts from origin at $t=0$ with a velocity $5 \hat{i} \mathrm{~m} / \mathrm{s}$ and moves in $x-y$ plane under action of a force which produces a constant acceleration of $(3 \hat{i}+2 \hat{j}) \mathrm{m} / \mathrm{s}^2$. If the $x$-coordinate of the particle at that instant is $84 \mathrm{~m}$, then the speed of the particle at this time is $\sqrt{\alpha} \mathrm{m} / \mathrm{s}$. The value of $\alpha$ is___________.
The relation between time $t$ and distance $x$ for a moving body is given as $t=m x^{2}+n x$, where ${m}$ and ${n}$ are constants. The retardation of the motion is -
(Where $v$ stands for velocity)