From v-t graph, the

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2.Motion in Straight Line

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From the $v-t$ graph, the

A

speed at $t = 1\,s$ is $1.2\, m/s$

B

acceleration is $2\, m/s^2$

C

average speed during $1^{st}\, second$ is $1.5\, m/s$

D

speed of the particle can be zero

Solution

$v_{avg}=\frac{\text { distance }}{\text { time }}$

$v_{avg}=\frac{\frac{1}{2}(1+2) \times 1}{1}$

$=\frac{3}{2}=1.5 \mathrm{m} / \mathrm{s}$

Standard 11

Physics

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