From the following polynomials find out which of them has $(x-1)$ as a factor
$x^{3}+6 x^{2}-9 x-14$
$(x-1)$ is not a factor.
Without actual division, prove that $2 x^{4}-5 x^{3}+2 x^{2}-x+2$ is divisible by $x^{2}-3 x+2$
Without finding the cubes, factorise
$(x-2 y)^{3}+(2 y-3 z)^{3}+(3 z-x)^{3}$
Evaluate $66 \times 74$ without directly multiplying
Expand
$\left(\frac{2 x}{3}+\frac{3 y}{4}\right)^{2}$
Check whether $p(x)$ is a multiple of $g(x)$ or not, where
$p(x)=x^{3}-x+1, \quad g(x)=2-3 x$
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