Give the explanation of Gauss’s law for magnetic field.
According to the figure let closed surface $S$. This surface kept in a magnetic field $\vec{B}$. The flux associated with this surface we have to determine. Imagine surface $S$ is divided into small area element. One such element is $\overrightarrow{\Delta S}$ and magnetic field associated with it is $\vec{B}$. The magnetic flux for this element is defined as,
$\Delta \phi_{\mathrm{B}}=\overrightarrow{\mathrm{B}} \cdot \overrightarrow{\Delta \mathrm{S}}$
Total flux $\phi_{\mathrm{B}}=\sum_{\text {all }} \Delta \phi_{\mathrm{B}}=\sum_{\text {all }} \overrightarrow{\mathrm{B}} \cdot \Delta \overrightarrow{\mathrm{S}}=0 \quad \ldots$ $(1)$
The number of lines leaving the surface is equal to the number of lines entering it. Hence, the net magnetic flux is zero.
In equation $(1)$ "all" stands for 'all area elements $\Delta \mathrm{S}$ '.
Gauss's law for magnetism is as below :
"The magnetic flux through any closed surface is zero".
Note : In equation ... $(1)$ if $\Delta \mathrm{S} \rightarrow 0$, then
$\phi=\int \overrightarrow{\mathrm{B}} \cdot \overrightarrow{d \mathrm{~S}}=0$
This equation is also a Gauss's law.
A small bar magnet has a magnetic moment $1.2 \,A-m^2$. The magnetic field at a distance $ 0.1\, m $ on its axis will be : ($\mu_0 = 4\pi \times 10^{-7} \,T-m/A$)
What does the analog (similarity) of bar magnet’s and solenoid’s magnetic field lines suggest ?
The magnetic field lines due to a bar magnet are correctly shown in
Two magnets, each of magnetic moment $‘M’ $ are placed so as to form a cross at right angles to each other. The magnetic moment of the system will be
Magnetic lines of force