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5.Magnetism and Matter
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The magnetic potential at a point on the axial line of a bar magnet of dipole moment $M$ is $V$. What is the magnetic potential due to a bar magnet of dipole moment $\frac{M}{4}$ at the same point
A
$4\,V$
B
$2\,V$
C
$\frac{V}{2}$
D
$\frac{V}{4}$
Solution
(d)Magnetic potential at a distance d from the bar magnet on it's axial line is given by
$V = \frac{{{\mu _0}}}{{4\pi }}.\frac{M}{{{d^2}}}$ $⇒$ $V \propto M$ $⇒$ $\frac{{{V_1}}}{{{V_2}}} = \frac{{{M_1}}}{{{M_2}}}$
$⇒$ $\frac{V}{{{V_2}}} = \frac{M}{{M/4}}$ $⇒$ ${V_2} = \frac{V}{4}$
Standard 12
Physics
