Given that 1,g of water in liquid phase has volume 1,cm^3 and in vapour phase 1671, cm^3 at atmosphe

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11.Thermodynamics

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Given that $1\,g$ of water in liquid phase has volume $1\,cm^3$ and in vapour phase $1671\, cm^3$ at atmospheric pressure and the latent heat of vaporization of water is $2256\,J/g;$ the change in the internal energy in joules for $1\,g$ of water at $373\,K$ when it changes from liquid phase to vapour phase at the same temperature is ....... $J$

A

$2256$

B

$167$

C

$2089$

D

$1$

(JEE MAIN-2013) (NEET-2019)

Solution

$W = P\left( {dV} \right)$$ = 0.01 \times {10^5}\left( {1671 – 1} \right) \times {10^{ – 6}} = 167\,J$

$Q = \Delta U + W$

$\Delta U = Q – W = mL – 167$$ = 2256 – 167 = 2089\,J$

Standard 11

Physics

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