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10-2.Transmission of Heat
normal
Hot water cools from $60\,^oC$ to $50\,^oC$ in the first $10\, min$ and to $42\,^oC$ in the next $10\, min$. The temperature of the surrounding is ........ $^oC$
A
$50$
B
$10$
C
$15$
D
$20$
Solution
$\frac{\mathrm{T}_{1}-\mathrm{T}_{2}}{\mathrm{t}}=\mathrm{k}\left(\frac{\mathrm{T}_{1}+\mathrm{T}_{2}}{2}-\mathrm{T}_{0}\right)$
$\frac{60-50}{10}=\mathrm{k}\left(\frac{60+50}{2}-\mathrm{T}_{0}\right)$
$\frac{50-42}{10}=\mathrm{k}\left(\frac{50+42}{2}-\mathrm{T}_{0}\right)$
By solving $\mathrm{T}_{0}=10^{\circ} \mathrm{C}$
Standard 11
Physics