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6-2.Equilibrium-II (Ionic Equilibrium)
medium
How many grams of $Ca{C_2}{O_4}$ (molecular weight $= 128$) on dissolving in distilled water will give a saturated solution $[{K_{sp}}(Ca{C_2}{O_4}) = 2.5 \times {10^{ - 9}}$ $mo{l^2}{l^{ - 2}}]$
A
$0.0064$
B
$0.1280$
C
$0.0128$
D
$1.2800$
Solution
(a) Solubility of $Ca{C_2}{O_4} = \sqrt {{K_{sp}}} = \sqrt {2.5 \times {{10}^{ – 9}}} $
$ = 5 \times {10^{ – 5}}\,mol{L^{ – 1}}$
$ = 5 \times {10^{ – 5}} \times 128 = 640 \times {10^{ – 5}}$$ = 0.0064\,g$
Standard 11
Chemistry