Hydrogen $(H)$, deuterium $(D)$, singly ionized helium $(He^+)$ and doubly ionized lithium $(Li^{++})$ all have one electron around the nucleus. Consider $n = 2$ to $n = 1$ transition. The wavelengths of emitted radiations are $\lambda_1, \lambda_2 \lambda_3$ and $\lambda_4$ respectively.
$\lambda_1 = \lambda_2 = 4 \lambda_3 = 9 \lambda_4$
$4 \lambda_1 = 2 \lambda_2 = 2 \lambda_3 = \lambda_4$
$\lambda_1 = 2 \lambda_2 = 2 \sqrt 2 \lambda_3 = 3 \sqrt 2 \lambda_4$
$\lambda_1 = \lambda_2 = 2 \lambda_3 = 3 \sqrt 2 \lambda_4$
The following diagram indicates the energy levels of a certain atom when the system moves from $4E$ level to $E$. A photon of wavelength $\lambda _1$ is emitted. The wavelength of photon produced during it's transition from $\frac{7}{3}E$ level to $E$ is $\lambda_2$. The ratio $\frac{{{\lambda _1}}}{{{\lambda _2}}}$ will be
What was the thickness of the gold foil kept in the Geiger-Marsden scattering experiment?
Hydrogen atom is excited from ground state to another state with principal quantum number equal to $4$. Then the number of spectral lines in the emission spectra will be
In an atom, two electrons move around the nucleus in circular orbits of radii $R$ and $4R.$ The ratio of the time taken by them to complete one revolution is : (neglect electric interaction)
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