Absorption transitions between first and fourth energy states of hydrogen atom are 3. emission trans

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12.Atoms

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The absorption transitions between the first and the fourth energy states of hydrogen atom are $3.$ The emission transitions between these states will be

A

$3$

B

$4$

C

$5$

D

$6$

Solution

(d) By using ${N_E} = \frac{{n(n – 1)}}{2}$==> ${N_E} = \frac{{4(4 – 1)}}{2} = 6$

Standard 12

Physics

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