If $P = \frac{{{A^3}}}{{{B^{5/2}}}}$ and $\Delta A$ is absolute error in $A$ and $\Delta B$ is absolute error in $B$ then absolute error $\Delta P$ in $P$ is
If $P = \frac{{{A^3}}}{{{B^{5/2}}}}$ and $\Delta A$ is absolute error in $A$ and $\Delta B$ is absolute error in $B$ then absolute error $\Delta P$ in $P$ is
- A
$\Delta P = \pm \left( { 3 \frac{{\Delta A}}{A} + \frac{5}{2}\frac{{\Delta B}}{B}} \right)P$
- B
$\Delta P = \pm \left( { 3 \frac{{\Delta A}}{A} + \frac{5}{2}\frac{{\Delta B}}{B}} \right)$
- C
$\Delta P = \pm \left( { 3 \frac{{\Delta A}}{A} - \frac{5}{2}\frac{{\Delta B}}{B}} \right)P$
- D
$\Delta P = \pm \left( { 3 \frac{{\Delta A}}{B} - \frac{5}{2}\frac{{\Delta B}}{A}} \right)P$
Similar Questions
In an experiment four quantities $a, b, c$ and $d$ are measured with percentage error $1\%, 2\%, 3\%$ and $4\%$ respectively. Quantity $w$ is calculated as follows $w\, = \,\frac{{{a^4}{b^3}}}{{{c^2}\sqrt D }}$ error in the measurement of $w$ is .......... $\%$
In an experiment four quantities $a, b, c$ and $d$ are measured with percentage error $1\%, 2\%, 3\%$ and $4\%$ respectively. Quantity $w$ is calculated as follows $w\, = \,\frac{{{a^4}{b^3}}}{{{c^2}\sqrt D }}$ error in the measurement of $w$ is .......... $\%$
Time intervals measured by a clock give the following readings :
$1.25 \;s , 1.24\; s , 1.27\; s , 1.21 \;s$ and $1.28\; s$
What is the percentage relative error of the observations?
Time intervals measured by a clock give the following readings :
$1.25 \;s , 1.24\; s , 1.27\; s , 1.21 \;s$ and $1.28\; s$
What is the percentage relative error of the observations?
- [NEET 2020]
Error in volume of a sphere is $6\%$. Error in its radius will be .......... $\%$
Error in volume of a sphere is $6\%$. Error in its radius will be .......... $\%$
Two clocks are being tested against a standard clock located in a national laboratory. At $12: 00: 00$ noon by the standard clock, the readings of the two clocks are
$\begin{array}{ccc} & \text {Clock} 1 & \text {Clock} 2 \\ \text { Monday } & 12: 00: 05 & 10: 15: 06 \\ \text { Tuesday } & 12: 01: 15 & 10: 14: 59 \\ \text { Wednesday } & 11: 59: 08 & 10: 15: 18 \\ \text { Thursday } & 12: 01: 50 & 10: 15: 07 \\ \text { Friday } & 11: 59: 15 & 10: 14: 53 \\ \text { Saturday } & 12: 01: 30 & 10: 15: 24 \\ \text { Sunday } & 12: 01: 19 & 10: 15: 11\end{array}$
If you are doing an experiment that requires precision time interval measurements, which of the two clocks will you prefer?
Two clocks are being tested against a standard clock located in a national laboratory. At $12: 00: 00$ noon by the standard clock, the readings of the two clocks are
$\begin{array}{ccc} & \text {Clock} 1 & \text {Clock} 2 \\ \text { Monday } & 12: 00: 05 & 10: 15: 06 \\ \text { Tuesday } & 12: 01: 15 & 10: 14: 59 \\ \text { Wednesday } & 11: 59: 08 & 10: 15: 18 \\ \text { Thursday } & 12: 01: 50 & 10: 15: 07 \\ \text { Friday } & 11: 59: 15 & 10: 14: 53 \\ \text { Saturday } & 12: 01: 30 & 10: 15: 24 \\ \text { Sunday } & 12: 01: 19 & 10: 15: 11\end{array}$
If you are doing an experiment that requires precision time interval measurements, which of the two clocks will you prefer?
The length of a cylinder is measured with a metre rod having least count $0.1 \;cm$. Its diameter is measured with vernier calipers having least count $0.01\; cm$. If the length and diameter of the cylinder are $5.0\; cm$ and $2.00\; cm$, respectively, then the percentage error in the calculated value of volume will be
The length of a cylinder is measured with a metre rod having least count $0.1 \;cm$. Its diameter is measured with vernier calipers having least count $0.01\; cm$. If the length and diameter of the cylinder are $5.0\; cm$ and $2.00\; cm$, respectively, then the percentage error in the calculated value of volume will be