1.Units, Dimensions and Measurement
easy

The radius of a sphere is $(5.3 \pm 0.1) \,cm$. The percentage error in its volume is

A

$\frac{{0.1}}{{5.3}} \times 100$

B

$3 \times \frac{{0.1}}{{5.3}} \times 100$

C

$\frac{{0.1 \times 100}}{{3.53}}$

D

$3 + \frac{{0.1}}{{5.3}} \times 100$

Solution

(b) $V={\frac{4}{3}}{\pi}r^3$

$\%$ error in volume $ = 3 \times \% $ error in radius.

$ = \frac{{3 \times 0.1}}{{5.3}} \times 100$

Standard 11
Physics

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