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1.Units, Dimensions and Measurement
easy
The radius of a sphere is $(5.3 \pm 0.1) \,cm$. The percentage error in its volume is
A
$\frac{{0.1}}{{5.3}} \times 100$
B
$3 \times \frac{{0.1}}{{5.3}} \times 100$
C
$\frac{{0.1 \times 100}}{{3.53}}$
D
$3 + \frac{{0.1}}{{5.3}} \times 100$
Solution
(b) $V={\frac{4}{3}}{\pi}r^3$
$\%$ error in volume $ = 3 \times \% $ error in radius.
$ = \frac{{3 \times 0.1}}{{5.3}} \times 100$
Standard 11
Physics
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