If $\left| {\begin{array}{*{20}{c}}
{a - b - c}&{2a}&{2a}\\
{2b}&{b - c - a}&{2b}\\
{2c}&{2c}&{c - a - b}
\end{array}} \right|$ $ = \left( {a + b + c} \right)\,{\left( {x + a + b + c} \right)^2}$ , $x   \ne 0$ and $a + b + c \ne 0$, then $x$ is equal to

  • [JEE MAIN 2019]
  • A

    $abc$

  • B

    $ - 2 \left( {a + b + c} \right)$

  • C

    $ 2 \left( {a + b + c} \right)$

  • D

    $ - \left( {a + b + c} \right)$

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