Gujarati
Hindi
2.Motion in Straight Line
easy

If $x \propto {t^{5/2}}$ , then

A

$v \propto {t^{3/2}}$

B

$a \propto \sqrt t $

C

both$ (A)$ and $(B)$

D

$v \propto \sqrt t $

Solution

Given $x \propto t^2 \quad \Rightarrow x= Kt ^2 \quad$ where $K = constant$

$\therefore$ Velocity of the particle $v =\frac{ dx }{ dt }=2 Kt$

$\therefore$ Acceleration of the particle $a =\frac{ dv }{ dt }=2 K = constant$

Standard 11
Physics

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