If $L_1$ and $L_2$ are the lengths of the first and second resonating air columns in a resonance tube, then the wavelength of the note produced is
$2(L_2 + L_1)$
$2(L_2 - L_1)$
$2\left( {{L_2} - \frac{{{L_1}}}{2}} \right)$
$2\left( {{L_2} + \frac{{{L_1}}}{2}} \right)$
A sound absorber attenuates the sound level by $20\,\, dB$. The intensity decrease by a factor of
In a resonance tube experiment, the first resonance is obtained for $10\, cm$ of air column and the second for $32\, cm$. The end correction for this apparatus is ....$cm$
The stationary wave $y = 2a{\mkern 1mu} \,\,sin\,\,{\mkern 1mu} kx{\mkern 1mu} \,\,cos{\mkern 1mu} \,\omega t$ in a stretched string is the result of superposition of $y_1 = a\,sin\,(kx -\omega t)$ and
A pulse shown here is reflected from the rigid wall $A$ and then from free end $B.$ The shape of the string after these $2$ reflection will be
The displacement $y$ of a wave travelling in the $x-$ direction is given by $y = {10^{ - 4}}\sin \left( {600t - 2x+\frac{\pi }{3}} \right)$ metre, where $x$ is expressed in metres and $t$ in seconds. The speed of the wave in $ms^{-1}$, is