If $E$ and $B$ denote electric and magnetic fields respectively, which of the following is dimensionless
$\sqrt {{\mu _0}{\varepsilon _0}} \frac{E}{B}$
$ {{\mu _0}{\varepsilon _0}} \frac{E}{B}$
${\mu _0}{\varepsilon _0}{\left( {\frac{B}{E}} \right)^2}$
$\frac{E}{{{\varepsilon _0}}}\frac{{{\mu _0}}}{B}$
The ratio of the magnitude of the magnetic field and electric field intensity of a plane electromagnetic wave in free space of permeability $\mu_0$ and permittivity $\varepsilon_0$ is (Given that $c$ - velocity of light in free space)
There exists a uniform magnetic and electric field of magnitude $1\, T$ and $1\, V/m$ respectively along positive $y-$ axis. A charged particle of mass $1\,kg$ and of charge $1\, C$ is having velocity $1\, m/sec$ along $x-$ axis and is at origin at $t = 0.$ Then the co-ordinates of particle at time $\pi$ seconds will be :-
An electromagnetic wave with frequency $\omega $ and wavelength $\lambda $ travels in the $+y$ direction. Its magnetic field is along $+x$ axis. The vector equation for the associated electric field (of amplitude $E_0$) is
A $27\, mW$ lager beam has a cross -sectional area of $10\, mm^2$. The magnitude of the maximum electric field in this electromagnetic wave is given by:........$kV/m$ [Given permittivity of space ${ \in _0} = 9 \times {10^{ - 12}}\, SI\, units$, speed of light $c = 3 \times 10^8\, m/s$]
A radiation is emitted by $1000\, W$ bulb and it generates an electric field and magnetic field at $P$, placed at a distance of $2\, m$. The efficiency of the bulb is $1.25 \%$. The value of peak electric field at $P$ is $x \times 10^{-1} \,V / m$. Value of $x$ is. (Rounded-off to the nearest integer)
[Take $\varepsilon_{0}=8.85 \times 10^{-12} C ^{2} N ^{-1} m ^{-2}, c =3 \times 10^{8}$ $ms ^{-1}$ ]