Gujarati
Hindi
8.Electromagnetic waves
easy

The electric field of plane electromagnetic wave of amplitude $2\,V/m$ varies with time, propagating along $z-$ axis. The average energy density of magnetic field (in $J/m^3$ ) is

A

$13.29 \times 10^{-12}$

B

$8.85 \times 10^{-12}$

C

$17.72 \times 10^{-12}$

D

$4.43 \times 10^{-12}$

Solution

$\left\langle {{{\rm{u}}_{\rm{B}}}} \right\rangle  = \left\langle {{{\rm{u}}_{\rm{E}}}} \right\rangle $

$=\frac{1}{4} \varepsilon_{0} \mathrm{E}_{0}^{2}=\frac{1}{4} \times 8.85 \times 10^{-12}(2)^{2} $

$=8.85 \times 10^{-12} \mathrm{\,J} / \mathrm{m}^{3} $

Standard 12
Physics

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