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13.Nuclei
medium
If $r_1$ and $r_2$ are the radii of the atomic nuclei of mass number $64$ and $125$ respectively, then the ratio $(r_1/r_2)$ is
A
$\frac{64}{125}$
B
$\sqrt {\frac{{64}}{{125}}} $
C
$\frac{5}{4}$
D
$\frac{4}{5}$
Solution
$\mathrm{r}=\mathrm{r}_{0} \mathrm{A}^{1 / 3}$
$\frac{\mathrm{r}_{1}}{\mathrm{r}_{2}}=\left(\frac{\mathrm{A}_{1}}{\mathrm{A}_{2}}\right)^{1 / 3}=\left(\frac{64}{125}\right)^{1 / 3}=\frac{4}{5}$
Standard 12
Physics