If r_1 and r_2 are the radii of the atomic nu | vedclass

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Question

$\mathrm{r}=\mathrm{r}_{0} \mathrm{A}^{1 / 3}$

$\frac{\mathrm{r}_{1}}{\mathrm{r}_{2}}=\left(\frac{\mathrm{A}_{1}}{\mathrm{A}_{2}}\right)^{1 / 3}=\l

Vedclass · Accepted Answer

$\frac{4}{5}$

Vedclass · Answer

$\mathrm{r}=\mathrm{r}_{0} \mathrm{A}^{1 / 3}$

$\frac{\mathrm{r}_{1}}{\mathrm{r}_{2}}=\left(\frac{\mathrm{A}_{1}}{\mathrm{A}_{2}}\right)^{1 / 3}=\left(\frac{64}{125}\right)^{1 / 3}=\frac{4}{5}$

If $r_1$ and $r_2$ are the radii of the atomic nuclei of mass number $64$ and $125$ respectively, then the ratio $(r_1/r_2)$ is

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