Assume that protons and neutrons have equal m | vedclass

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Question

$	ext { density of nuclei }=\frac{	ext { mass of nuclei }}{	ext { volume of nuclei }}$

$ho=\frac{1.6 	imes 10^{-27} A }{\frac{4}{3} \pi\left(

Vedclass · Accepted Answer

$11$

Vedclass · Answer

$	ext { density of nuclei }=\frac{	ext { mass of nuclei }}{	ext { volume of nuclei }}$

$ho=\frac{1.6 	imes 10^{-27} A }{\frac{4}{3} \pi\left(1.5 	imes 10^{-15}ight)^3 A } $

$=\frac{1.6 	imes 10^{-27}}{14.14 	imes 10^{-45}}=0.113 	imes 10^{18}$

$ho_{ W }=10^3$

$	ext { Hence } \frac{ho}{ho_w}=11.31 	imes 10^{13}$

Assume that protons and neutrons have equal masses. Mass of a nucleon is $1.6 \times 10^{-27}\,kg$ and radius of nucleus is $1.5 \times 10^{-15} A ^{1 / 3}\,m$. The approximate ratio of the nuclear density and water density is $n \times 10^{13}$. The value of $n$ is $.................$

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