If 5% of the energy supplied to a bulb is irr | vedclass

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Question

Energy radiated as visible light

$=\frac{5}{100} 	imes 100=5 \mathrm{\,J} / \mathrm{s}$

Let $n$ be the number of photons emitted per sec

The

Vedclass · Accepted Answer

$1.4	imes10^{19}$

Vedclass · Answer

Energy radiated as visible light

$=\frac{5}{100} 	imes 100=5 \mathrm{\,J} / \mathrm{s}$

Let $n$ be the number of photons emitted per sec

Then

$\mathrm{nhv}=\mathrm{n} \frac{\mathrm{hc}}{\lambda}=5$

$	herefore \quad \mathrm{n}=\frac{5 \lambda}{\mathrm{hc}}=\frac{5 	imes 5.6 	imes 10^{-7}}{\left(6.6 	imes 10^{-34}ight)\left(3 	imes 10^{8}ight)}=1.4 	imes 10^{19}$

If $5\%$ of the energy supplied to a bulb is irradiated as visible light, how many quanta are emitted per sec by a $100$ $watt$ lamp ? Assume wavelength of visible light as $5.6\times10^{-5}\, cm$.

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