Photon and electron are given same energy ({10^{ - 20}}J) . Wavelength associated with photon and el

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11.Dual Nature of Radiation and matter

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Photon and electron are given same energy $({10^{ - 20}}J)$. Wavelength associated with photon and electron are ${\lambda _{Ph}}$ and ${\lambda _{el}}$ then correct statement will be

A

${\lambda _{Ph}} > {\lambda _{el}}$

B

${\lambda _{Ph}} < {\lambda _{el}}$

C

${\lambda _{Ph}} = {\lambda _{el}}$

D

$\frac{{{\lambda _{el}}}}{{{\lambda _{Ph}}}} = C$

Solution

(a) Wavelength of photon will be greater than that of electron because mass of photon is less than that of electron

$ \Rightarrow {\lambda _{{\rm{ph}}}} > {\lambda _e}$

Standard 12

Physics

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