Photon and electron are given same energy $({10^{ - 20}}J)$. Wavelength associated with photon and electron are ${\lambda _{Ph}}$ and ${\lambda _{el}}$ then correct statement will be
${\lambda _{Ph}} > {\lambda _{el}}$
${\lambda _{Ph}} < {\lambda _{el}}$
${\lambda _{Ph}} = {\lambda _{el}}$
$\frac{{{\lambda _{el}}}}{{{\lambda _{Ph}}}} = C$
A convex lens of focal length $40 \mathrm{~cm}$ forms an image of an extended source of light on a photoelectric cell. A current I is produced. The lens is replaced by another convex lens having the same diameter but focal length $20 \mathrm{~cm}$. The photoelectric current now is:
The time taken by a photoelectron to come Out after the photon strikes is approximately
The work functions of Caesium $(Cs)$,Potassium $(K)$ and Sodium $(Na)$ are $2.14\,eV,2.30\,eV$ and $2.75\,eV$ respectively. If incident electromagnetic radiation has an incident energy of $2.20\, eV$, which of these photosensitive surfaces may emit photoelectrons?
In photo electric effect
$A.$ The photocurrent is proportional to the intensity of the incident radiation.
$B.$ Maximum Kinetic energy with which photoelectrons are emitted depends on the intensity of incident light.
$C.$ Max. $K.E$ with which photoelectrons are emitted depends on the frequency of incident light.
$D.$ The emission of photoelectrons require a minimum threshold intensity of incident radiation.
$E.$ Max. K.E of the photoelectrons is independent of the frequency of the incident light.
Choose the correct answer from the options given below:
The value of Planck's constant is