If $A=\{x \in R:|x|<2\}$ and $B=\{x \in R:|x-2| \geq 3\}$ then
$A \cup B=R-(2,5)$
$A \cap B=(-2,-1)$
$B-A=R-(-2,5)$
$A-B=[-1,2)$
Let $A = \{a, b, c\}, B = \{b, c, d\}, C = \{a, b, d, e\},$ then $A \cap (B \cup C)$ is
If $A$ and $B$ are any two sets, then $A \cup (A \cap B) $ is equal to
Show that for any sets $\mathrm{A}$ and $\mathrm{B}$, $A=(A \cap B) \cup(A-B)$ and $A \cup(B-A)=(A \cup B).$
If $A = \{ x:x$ is a natural number $\} ,B = \{ x:x$ is an even natural number $\} $ $C = \{ x:x$ is an odd natural number $\} $ and $D = \{ x:x$ is a prime number $\} ,$ find
$A \cap B$
Consider the following relations :
$(1) \,\,\,A - B = A - (A \cap B)$
$(2) \,\,\,A = (A \cap B) \cup (A - B)$
$(3) \,\,\,A - (B \cup C) = (A - B) \cup (A - C)$
which of these is/are correct