If $A$ and $B$ are any two sets, then $A \cap (A \cup B)$ is equal to
$A$
$B$
${A^c}$
${B^c}$
(a) $A \cap (A \cup B) = A$, $[\because A \subseteq B \cup A]$.
Find sets $A, B$ and $C$ such that $A \cap B, B \cap C$ and $A \cap C$ are non-empty sets and $A \cap B \cap C=\varnothing$
The shaded region in given figure is-
If the sets $A$ and $B$ are defined as $A = \{ (x,\,y):y = {1 \over x},\,0 \ne x \in R\} $ $B = \{ (x,y):y = – x,x \in R\} $, then
If $A=\{3,6,9,12,15,18,21\}, B=\{4,8,12,16,20\},$ $C=\{2,4,6,8,10,12,14,16\}, D=\{5,10,15,20\} ;$ find
$D-B$
$A-(A-B)$ is
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