If $A.M.$ and $G.M.$ of roots of a quadratic equation are $8$ and $5,$ respectively, then obtain the quadratic equation.
Let the root of the quadratic equation be $a$ and $b$
According to the given condition,
$A. M.=\frac{a+b}{2}=8 \Rightarrow a+b=16$ ........$(1)$
$G.M.$ $=\sqrt{a b}=5 \Rightarrow a b=25$ .........$(2)$
The quadratic equation is given by,
$x^{2}-x(\text { Sumof roots })+(\text { Product of roots })=0$
$x^{2}-x(a+b)+(a b)=0$
$x^{2}-16 x+25=0$ [ Using $(1)$ and $(2)$ ]
Thus, the required quadratic equation is $x^{2}-16 x+25=0$
Let $\frac{1}{16}, a$ and $b$ be in $G.P.$ and $\frac{1}{ a }, \frac{1}{ b }, 6$ be in $A.P.,$ where $a , b >0$. Then $72( a + b )$ is equal to ...... .
If the arithmetic and geometric means of $a$ and $b$ be $A$ and $G$ respectively, then the value of $A - G$ will be
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