If $A=\{3,5,7,9,11\}, B=\{7,9,11,13\}, C=\{11,13,15\}$ and $D=\{15,17\} ;$ find

$\left( {A \cap B} \right) \cap \left( {B \cup C} \right)$

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$(A \cap B) \cap(B \cup C)=\{7,9,11\} \cap\{7,9,11,13,15\}=\{7,9,11\}$

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