- Home
- Standard 10
- Mathematics
8. Introduction to Trigonometry
medium
If $0 < \theta < 90$ and $\sin \theta=\cos 30,$ then $2 \tan ^{2} \theta-1=\ldots \ldots \ldots \ldots .$
A
$5$
B
$4$
C
$3$
D
$0$
Solution
$\sin \theta=\cos 30 \quad \therefore \sin \theta=\frac{\sqrt{3}}{2} \quad \therefore \theta=60$
Now, $2 \tan ^{2} \theta-1=2 \tan ^{2} 60-1=2(\sqrt{3})^{2}-1=6-1=5$
Standard 10
Mathematics