If tan θ=frac{1}{√{5}} and θ lies in first quadrant, value of cos θ is :

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If $\tan \theta=\frac{1}{\sqrt{5}}$ and $\theta$ lies in the first quadrant, the value of $\cos \theta$ is :

A

$\sqrt{\frac{5}{6}}$

B

$-\sqrt{\frac{5}{6}}$

C

$\frac{1}{\sqrt{6}}$

D

$-\frac{1}{\sqrt{6}}$

Solution

(a)

$\cos \theta=\frac{\sqrt{5}}{\sqrt{6}}$

Standard 11

Physics

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