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A cuboidal block has dimension $(1.5 × 1.5 × 1.0)\ \ cm$ what is the surface area of cuboid (in $cm^2$)
A
$5.2$
B
$10.4$
C
$5.25$
D
$10.5$
Solution
Surface Area $=2[a b+b c+c a]$
$=2[1.5 \times 1.5+1.5 \times 1.0+1.5 \times 1.0]$
$=2[2.25+1.50+1.50]$
$=2[2.2+1.5+1.5]$
$=2 \times 5.2=10.4 \mathrm{\,cm}^{2}$
Standard 11
Physics