If t =√{ x }+4 , then left(frac{ dx }{ dt }right)_{ t =4} is.

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2.Motion in Straight Line

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If $t =\sqrt{ x }+4$, then $\left(\frac{ dx }{ dt }\right)_{ t =4}$ is.

A

$4$

B

$0$

C

$8$

D

$16$

(JEE MAIN-2022)

Solution

$t =\sqrt{ x }+4$

$\Rightarrow x =( t -4)^{2}= t ^{2}-8 t +16$

$\Rightarrow \frac{ dx }{ dt }=2 t -8$

$\left.\Rightarrow \frac{ dx }{ dt }\right|_{ t =4}=2 \times 4-8=0$

Standard 11

Physics

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