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2.Motion in Straight Line
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જો $t =\sqrt{ x }+4$ છે, તો $\left(\frac{ dx }{ dt }\right)_{ t =4}$ નું મૂલ્ય.
A
$4$
B
$0$
C
$8$
D
$16$
(JEE MAIN-2022)
Solution
$t =\sqrt{ x }+4$
$\Rightarrow x =( t -4)^{2}= t ^{2}-8 t +16$
$\Rightarrow \frac{ dx }{ dt }=2 t -8$
$\left.\Rightarrow \frac{ dx }{ dt }\right|_{ t =4}=2 \times 4-8=0$
Standard 11
Physics
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