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1.Set Theory
medium
If $A =$ [$x:x$ is a multiple of $3$] and $B =$ [$x:x$ is a multiple of $5$], then $A -B$ is ($\bar A$ means complement of $A$)
A
$\bar A \cap B$
B
$A \cap \bar B$
C
$\bar A \cap \bar B$
D
$\overline {A \cap B} $
Solution
(b) $ A -B = A \cap B^c = A \cap $ $\bar B$.
Standard 11
Mathematics