1.Set Theory
medium

If $A =$ [$x:x$ is a multiple of $3$] and $B =$ [$x:x$ is a multiple of $5$], then $A -B$ is ($\bar A$ means complement of $A$)

A

$\bar A \cap B$

B

$A \cap \bar B$

C

$\bar A \cap \bar B$

D

$\overline {A \cap B} $

Solution

(b) $ A -B = A \cap B^c = A \cap $ $\bar B$.

Standard 11
Mathematics

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