3 and 4 .Determinants and Matrices
easy

यदि $A = \left[ {\begin{array}{*{20}{c}}1&{ - 2}&1\\2&1&3\end{array}} \right]$ और $B = \left[ {\begin{array}{*{20}{c}}2&1\\3&2\\1&1\end{array}} \right]$, तो ${(AB)^T} = $

A

$\left[ {\begin{array}{*{20}{c}}{ - 3}&{ - 2}\\{10}&7\end{array}} \right]$

B

$\left[ {\begin{array}{*{20}{c}}{ - 3}&{10}\\{ - 2}&7\end{array}} \right]$

C

$\left[ {\begin{array}{*{20}{c}}{ - 3}&{10}\\7&{ - 2}\end{array}} \right]$

D

$\left[ {\begin{array}{*{20}{c}}3&{10}\\2&7\end{array}} \right]$

Solution

(b) $AB = \left[ {\begin{array}{*{20}{c}}1&{ – 2}&1\\2&1&3\end{array}} \right]\left[ {\begin{array}{*{20}{c}}2&1\\3&2\\1&1\end{array}} \right]$

$AB = \left[ {\begin{array}{*{20}{c}}{ – 3}&{ – 2}\\{10}&7\end{array}} \right] \Rightarrow {(AB)^T} = \left[ {\begin{array}{*{20}{c}}{ – 3}&{10}\\{ – 2}&7\end{array}} \right]$.

Standard 12
Mathematics

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