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3 and 4 .Determinants and Matrices
easy
यदि $A = \left( {\begin{array}{*{20}{c}}i&1\\0&i\end{array}} \right)$, तो ${A^4}$ का मान होगा
A
$\left( {\begin{array}{*{20}{c}}1&{ - 4i}\\0&1\end{array}} \right)$
B
$\left( {\begin{array}{*{20}{c}}{ - 1}&{ - 4i}\\0&{ - 1}\end{array}} \right)$
C
$\left( {\begin{array}{*{20}{c}}{ - i}&4\\0&i\end{array}} \right)$
D
$\left( {\begin{array}{*{20}{c}}1&4\\0&1\end{array}} \right)$
Solution
(a) $A.A = \left[ {\begin{array}{*{20}{c}}{ – 1}&{2i}\\0&{ – 1}\end{array}} \right]$ ,
${A^4} = \left[ {\begin{array}{*{20}{c}}1&{ – 4i}\\0&1\end{array}} \right]$.
Standard 12
Mathematics