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3 and 4 .Determinants and Matrices
easy
જો $A = \left( {\begin{array}{*{20}{c}}1&{ - 2}&1\\2&1&3\end{array}} \right)$ અને $B = \left( {\begin{array}{*{20}{c}}2&1\\3&2\\1&1\end{array}} \right)$, તો ${(AB)^T}$ = . . ..
A
$\left( {\begin{array}{*{20}{c}}{ - 3}&{ - 2}\\{10}&7\end{array}} \right)$
B
$\left( {\begin{array}{*{20}{c}}{ - 3}&{10}\\{ - 2}&7\end{array}} \right)$
C
$\left( {\begin{array}{*{20}{c}}{ - 3}&7\\{10}&2\end{array}} \right)$
D
એકપણ નહી.
Solution
(b) $AB = \left( {\begin{array}{*{20}{c}} 1&{ – 2}&1 \\ 2&1&3 \end{array}} \right)$ $\left( {\begin{array}{*{20}{c}} 2&1 \\ 3&2 \\ 1&1 \end{array}} \right)$= $\left( {\begin{array}{*{20}{c}} { – 3}&{ – 2} \\ {10}&7 \end{array}} \right)$
${(AB)^T} = \left( {\begin{array}{*{20}{c}}{ – 3}&{10}\\{ – 2}&7\end{array}} \right)$.
Standard 12
Mathematics