3 and 4 .Determinants and Matrices
easy

જો $A = \left( {\begin{array}{*{20}{c}}1&{ - 2}&1\\2&1&3\end{array}} \right)$ અને $B = \left( {\begin{array}{*{20}{c}}2&1\\3&2\\1&1\end{array}} \right)$, તો ${(AB)^T}$ = . . ..

A

$\left( {\begin{array}{*{20}{c}}{ - 3}&{ - 2}\\{10}&7\end{array}} \right)$

B

$\left( {\begin{array}{*{20}{c}}{ - 3}&{10}\\{ - 2}&7\end{array}} \right)$

C

$\left( {\begin{array}{*{20}{c}}{ - 3}&7\\{10}&2\end{array}} \right)$

D

એકપણ નહી.

Solution

(b) $AB = \left( {\begin{array}{*{20}{c}}   1&{ – 2}&1 \\    2&1&3  \end{array}} \right)$  $\left( {\begin{array}{*{20}{c}}   2&1 \\    3&2 \\    1&1  \end{array}} \right)$= $\left( {\begin{array}{*{20}{c}}   { – 3}&{ – 2} \\    {10}&7  \end{array}} \right)$

${(AB)^T} = \left( {\begin{array}{*{20}{c}}{ – 3}&{10}\\{ – 2}&7\end{array}} \right)$.

Standard 12
Mathematics

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