3 and 4 .Determinants and Matrices
easy

If $A = \left[ {\begin{array}{*{20}{c}}3&5\\2&0\end{array}} \right]$ and $B = \left[ {\begin{array}{*{20}{c}}1&{17}\\0&{ - 10}\end{array}} \right]$ then $|AB|$ is equal to

A

$80$

B

$100$

C

$-110$

D

$92$

Solution

(b) Since $A$ and $ B $ are square matrix 

$\therefore $$|AB|\, = |A||B|$; $|A|\, = – 10;|B| = – 10$

$\therefore $$|AB|\, = 100$.

Standard 12
Mathematics

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