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3 and 4 .Determinants and Matrices
easy
If $A = \left[ {\begin{array}{*{20}{c}}3&5\\2&0\end{array}} \right]$ and $B = \left[ {\begin{array}{*{20}{c}}1&{17}\\0&{ - 10}\end{array}} \right]$ then $|AB|$ is equal to
A
$80$
B
$100$
C
$-110$
D
$92$
Solution
(b) Since $A$ and $ B $ are square matrix
$\therefore $$|AB|\, = |A||B|$; $|A|\, = – 10;|B| = – 10$
$\therefore $$|AB|\, = 100$.
Standard 12
Mathematics