3.Trigonometrical Ratios, Functions and Identities
easy

જો  $x = \sec \theta + \tan \theta ,$ તો  $x + \frac{1}{x} = $

A

$1$

B

$2\sec \theta $

C

$2$

D

$2\tan \theta $

Solution

(b) Given that $x = \sec \theta + \tan \theta $

$ \Rightarrow \,x + \frac{1}{x} = \sec \theta + \tan \theta + \frac{1}{{\sec \theta + \tan \theta }}$

$ = \sec \theta + \tan \theta + \sec \theta – \tan \theta = 2\sec \theta $

Standard 11
Mathematics

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