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3.Trigonometrical Ratios, Functions and Identities
easy
જો $x = \sec \theta + \tan \theta ,$ તો $x + \frac{1}{x} = $
A
$1$
B
$2\sec \theta $
C
$2$
D
$2\tan \theta $
Solution
(b) Given that $x = \sec \theta + \tan \theta $
$ \Rightarrow \,x + \frac{1}{x} = \sec \theta + \tan \theta + \frac{1}{{\sec \theta + \tan \theta }}$
$ = \sec \theta + \tan \theta + \sec \theta – \tan \theta = 2\sec \theta $
Standard 11
Mathematics
