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Mathematical Reasoning
easy
If $p, q, r$ are simple propositions with truth values $T, F, T$, then the truth value of $(\sim p \vee q)\; \wedge \sim r \Rightarrow p$ is
A
true
B
false
C
True if $r$ is false
D
True if $q$ is true
Solution
(a) $\sim p \vee q$ means $F \vee F = F, \sim r$ means $F(\sim p \vee q) \wedge \sim r$ means $F$
$[(\sim p \vee q)\; \wedge \sim r] \Rightarrow p$ means $T$
[ in $p \Rightarrow q$ we have $FTT$]
Standard 11
Mathematics